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@@ -243,8 +243,8 @@ pprod256 = 0; /* product of "primes up to 256" / "primes up to 46" */
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* do make this so.
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*
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* input:
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* h the h as in h*2^n-1
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* n the n as in h*2^n-1
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* h h as in h*2^n-1 (must be >= 1)
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* n n as in h*2^n-1 (must be >= 1)
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*
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* returns:
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* 1 => h*2^n-1 is prime
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@@ -267,13 +267,17 @@ lucas(h, n)
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* check arg types
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*/
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if (!isint(h)) {
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ldebug("lucas", "h is non-int");
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quit "FATAL: bad args: h must be an integer";
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}
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if (h < 1) {
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quit "FATAL: bad args: h must be an integer >= 1";
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}
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if (!isint(n)) {
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ldebug("lucas", "n is non-int");
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quit "FATAL: bad args: n must be an integer";
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}
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if (n < 1) {
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quit "FATAL: bad args: n must be an integer >= 1";
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}
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/*
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* reduce h if even
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@@ -484,9 +488,9 @@ lucas(h, n)
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* See the function gen_v1() for details on the value of v(1).
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*
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* input:
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* h - h as in h*2^n-1
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* n - n as in h*2^n-1
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* v1 - gen_v1(h,n) (see function below)
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* h - h as in h*2^n-1 (must be >= 1)
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* n - n as in h*2^n-1 (must be >= 1)
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* v1 - gen_v1(h,n) (must be >= 3) (see function below)
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*
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* returns:
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* u(2) - initial value for Lucas test on h*2^n-1
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@@ -499,6 +503,8 @@ gen_u2(h, n, v1)
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local r; /* low value: v(n) */
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local s; /* high value: v(n+1) */
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local hbits; /* highest bit set in h */
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local oldh; /* pre-reduced h */
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local oldn; /* pre-reduced n */
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local i;
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/*
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@@ -507,24 +513,45 @@ gen_u2(h, n, v1)
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if (!isint(h)) {
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quit "bad args: h must be an integer";
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}
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if (h < 0) {
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quit "bad args: h must be an integer >= 1";
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}
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if (!isint(n)) {
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quit "bad args: n must be an integer";
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}
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if (n < 1) {
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quit "bad args: n must be an integer >= 1";
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}
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if (!isint(v1)) {
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quit "bad args: v1 must be an integer";
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}
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if (v1 <= 0) {
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quit "bogus arg: v1 is <= 0";
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if (v1 < 3) {
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quit "bogus arg: v1 must be an integer >= 3";
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}
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/*
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* reduce h if even
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*
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* we will force h to be odd by moving powers of two over to 2^n
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*/
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oldh = h;
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oldn = n;
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shiftdown = fcnt(h,2); /* h % 2^shiftdown == 0, max shiftdown */
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if (shiftdown > 0) {
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h >>= shiftdown;
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n += shiftdown;
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}
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/*
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* enforce the h > 0 and n >= 2 rules
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*/
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if (h <= 0 || n < 1) {
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print " ERROR: h=":oldh, "n=":oldn, "reduced h=":h, "n=":n;
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quit "reduced args violate the rule: 0 < h < 2^n";
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}
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hbits = highbit(h);
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if (hbits >= n) {
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print " ERROR: h=":oldh, "n=":oldn, "reduced h=":h, "n=":n;
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quit "reduced args violate the rule: 0 < h < 2^n";
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}
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@@ -599,8 +626,8 @@ gen_u2(h, n, v1)
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* See the function gen_u2() for details.
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*
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* input:
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* h - h as in h*2^n-1
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* n - n as in h*2^n-1
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* h - h as in h*2^n-1 (must be >= 1)
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* n - n as in h*2^n-1 (must be >= 1)
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* v1 - gen_v1(h,n) (see function below)
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*
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* returns:
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@@ -638,9 +665,9 @@ gen_u0(h, n, v1)
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* x > 2
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*
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* input:
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* x - potential v(1) value
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* h - h as in h*2^n-1
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* n - n as in h*2^n-1
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* x potential v(1) value
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* h h as in h*2^n-1 (h must be odd >= 1)
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* n n as in h*2^n-1 (must be >= 1)
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*
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* returns:
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* 1 if v(1) == x for h*2^n-1
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@@ -657,9 +684,18 @@ rodseth_xhn(x, h, n)
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if (!isint(h)) {
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quit "bad args: h must be an integer";
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}
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if (iseven(h)) {
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quit "bad args: h must be an odd integer";
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}
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if (h < 1) {
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quit "bad args: h must be an integer >= 1";
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}
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if (!isint(n)) {
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quit "bad args: n must be an integer";
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}
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if (n < 1) {
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quit "bad args: n must be an integer >= 1";
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}
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if (!isint(x)) {
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quit "bad args: x must be an integer";
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}
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@@ -703,9 +739,9 @@ rodseth_xhn(x, h, n)
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* We can show that X > 2. See the comments in the rodseth_xhn(x,h,n) above.
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*
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* Some values of X satisfy more often than others. For example a large sample
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* of odd h, h multiple of 3 and large n (some around 1e4, some near 1e6, others
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* near 3e7) where the sample size was 66 973 365, here is the count of the
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* smallest value of X that satisfies conditions in Ref4, condition 1:
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* of odd h, h odd multiple of 3 and large n (some around 1e4, some near 1e6,
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* others near 3e7) where the sample size was 66 973 365, here is the count of
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* the smallest value of X that satisfies conditions in Ref4, condition 1:
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*
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* count X
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* ----------
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@@ -763,45 +799,88 @@ rodseth_xhn(x, h, n)
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* 1 161
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* 1 155
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*
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* It is important that we select the smallest possible v(1). While testing
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* various values of X for V(1) is fast, using larger than necessary values
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* of V(1) of can slow down calculating V(h).
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*
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* The above distribution was found to hold fairly well over many values of
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* odd h that are a multiple of 3 and for many values of n where h < 2^n.
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* odd h that are also a multiple of 3 and for many values of n where h < 2^n.
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* For example for in a sample size of 835823 numbers of the form h*2^n-1
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* where odd h >= 12996351 is a multiple of 3, n >= 12996351, these are the
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* smallest v(1) values that were found:
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*
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* smallest percentage
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* v(1) used
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* -------------------
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* 3 40.000%
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* 5 25.683%
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* 9 11.693%
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* 11 10.452%
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* 15 4.806%
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* 17 2.348%
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* 21 1.656%
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* 29 1.281%
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* 27 0.6881%
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* 35 0.4536%
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* 39 0.3121%
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* 41 0.1760%
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* 31 0.1414%
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* 45 0.1173%
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* 51 0.05576%
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* 55 0.03300%
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* 49 0.03185%
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* 59 0.02090%
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* 69 0.00980%
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* 65 0.009367%
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* 71 0.007205%
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* 57 0.006341%
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* 85 0.004611%
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* 81 0.004179%
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* 95 0.002882%
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* 99 0.001873%
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* 77 0.001153%
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* 53 0.0007205%
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* 67 0.0005764%
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* 125 0.0005764%
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* 105 0.0005764%
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* 87 0.0004323%
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* 111 0.0004323%
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* 101 0.0002882%
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* 83 0.0001441%
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* 127 0.0001196%
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*
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* When h * 2^n-1 is prime and h is an odd multiple of 3, a smallest v(1) that
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* is even is extremely rate. Of the list of 127287 known primes of the form
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* h*2^n-1 when h was a multiple of 3, none has an smallest v(1) that was even.
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*
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* About 1 out of 835000 cases when h is a multiple of 3 use v(1) > 127 as the
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* smallest value of v(1).
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*
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* Given this information, when odd h is a multiple of 3 we try, in order,
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* these values of X:
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* these sorted values of X:
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*
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* 3, 5, 9, 11, 15, 17, 21, 29, 20, 27, 35, 36, 39, 41, 45, 32, 51, 44,
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* 56, 49, 59, 57, 65, 55, 69, 71, 77, 81, 66, 95, 80, 67, 84, 99, 72,
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* 74, 87, 90, 104, 101, 105, 109, 116, 111, 92
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* 3, 5, 9, 11, 15, 17, 21, 27, 29, 31, 35, 39, 41, 45, 49, 51, 53, 55,
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* 57, 59, 65, 67, 69, 71, 77, 81, 83, 85, 87, 95, 99, 101, 105, 111, 125
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*
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* And stop on the first value of X where:
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*
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* jacobi(X-2, h*2^n-1) == 1
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* jacobi(X+2, h*2^n-1) == -1
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*
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* If no value in that list works, we start simple search starting with X = 120
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* and incrementing by 1 until a value of X is found.
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* If no value in that list works, we start simple search starting with X = 12/
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* and incrementing by 2 until a value of X is found.
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*
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* The x_tbl[] matrix contains those common values of X to try in order.
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* If all x_tbl_len fail to satisfy Ref4 condition 1, then we begin a
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* linear search at next_x until we find a proper X value.
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*
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* IMPORTANT NOTE: Using this table will not find the smallest possible v(1)
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* for a given h and n. This is not a problem because using
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* a larger value of v(1) does not impact the primality test.
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* Furthermore after lucas(h, n) generates a few u(n) terms,
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* the values will wrap (due to computing mod h*2^n-1).
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* Finally on average, about 1/4 of the values of X work as
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* v(1) for a given n when h is a multiple of 3. Skipping
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* rarely used v(1) will not doom gen_v1() to a long search.
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*/
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x_tbl_len = 45;
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x_tbl_len = 35;
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mat x_tbl[x_tbl_len];
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x_tbl = {
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3, 5, 9, 11, 15, 17, 21, 29, 20, 27, 35, 36, 39, 41, 45, 32, 51, 44,
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56, 49, 59, 57, 65, 55, 69, 71, 77, 81, 66, 95, 80, 67, 84, 99, 72,
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74, 87, 90, 104, 101, 105, 109, 116, 111, 92
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3, 5, 9, 11, 15, 17, 21, 27, 29, 31, 35, 39, 41, 45, 49, 51, 53, 55,
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57, 59, 65, 67, 69, 71, 77, 81, 83, 85, 87, 95, 99, 101, 105, 111, 125
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};
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next_x = 120;
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next_x = 127;
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/*
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* gen_v1 - compute the v(1) for a given h*2^n-1 if we can
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@@ -956,8 +1035,8 @@ next_x = 120;
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***
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*
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* input:
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* h h as in h*2^n-1
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* n n as in h*2^n-1
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* h h as in h*2^n-1 (h must be odd >= 1)
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* n n as in h*2^n-1 (must be >= 1)
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*
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* output:
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* returns v(1), or -1 is there is no quick way
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|
@@ -974,9 +1053,18 @@ gen_v1(h, n)
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if (!isint(h)) {
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quit "bad args: h must be an integer";
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}
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if (iseven(h)) {
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quit "bad args: h must be an odd integer";
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}
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if (h < 1) {
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quit "bad args: h must be an integer >= 1";
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}
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if (!isint(n)) {
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quit "bad args: n must be an integer";
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}
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if (n < 1) {
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quit "bad args: n must be an integer >= 1";
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}
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/*
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|
* check for Case 1: (h mod 3 != 0)
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|
|
@@ -995,6 +1083,11 @@ gen_v1(h, n)
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*
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* jacobi(X-2, h*2^n-1) == 1 part 1
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* jacobi(X+2, h*2^n-1) == -1 part 2
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*
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* NOTE: If we wanted to be super optimial, we would cache
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* jacobi(X+2, h*2^n-1) that that when we increment X
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* to the next odd value, the now jacobi(X-2, h*2^n-1)
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* does not need to be re-evaluted.
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*/
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for (i=0; i < x_tbl_len; ++i) {
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@@ -1015,17 +1108,13 @@ gen_v1(h, n)
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}
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/*
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* We are in that rare case (about 1 in 2 300 000) where none of the
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* We are in that rare case (about 1 in 835 000) where none of the
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* common X values satisfy Ref4 condition 1. We start a linear search
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* at next_x from here on.
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*
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* However, we also need to keep in mind that when x+2 >= 257, we
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* need to verify that gcd(x-2, h*2^n-1) == 1 and
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* and to verify that gcd(x+2, h*2^n-1) == 1.
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* of odd vules at next_x from here on.
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*/
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x = next_x;
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while (rodseth_xhn(x, h, n) != 1) {
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++x;
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x += 2;
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}
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/* finally found a v(1) value */
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ldebug("gen_v1", "h= " + str(h) + " n= " + str(n) +
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@@ -1457,8 +1546,8 @@ legacy_d_qval[7] = 19; legacy_v1_qval[7] = 74; /* a=38 b=1 r=2 */
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***
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*
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* input:
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* h h as in h*2^n-1
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* n n as in h*2^n-1
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* h h as in h*2^n-1 (must be >= 1)
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* n n as in h*2^n-1 (must be >= 1)
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*
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* output:
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* returns v(1), or -1 is there is no quick way
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@@ -1470,6 +1559,22 @@ legacy_gen_v1(h, n)
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local val_mod; /* h*2^n-1 mod 'D' */
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local i;
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/*
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* check arg types
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*/
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if (!isint(h)) {
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quit "bad args: h must be an integer";
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}
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if (h < 1) {
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quit "bad args: h must be an integer >= 1";
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}
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if (!isint(n)) {
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quit "bad args: n must be an integer";
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}
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if (n < 1) {
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quit "bad args: n must be an integer >= 1";
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}
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/*
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* check for case 1
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*/
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