NAME rcmul - REDC multiplication SYNOPSIS rcmul(x, y, m) TYPES x integer y integer m odd positive integer return integer v, 0 <= v < m. DESCRIPTION Let B be the base calc uses for representing integers internally (B = 2^16 for 32-bit machines, 2^32 for 64-bit machines) and N the number of words (base-B digits) in the representation of m. Then rcmul(x,y,m) returns the value of B^-N * x * y % m, where the inverse implicit in B^-N is modulo m and the modulus operator % gives the least non-negative residue. The normal use of rcmul() may be said to be that of multiplying modulo m values encoded by rcin() and REDC functions, as in: rcin(x * y, m) = rcmul(rcin(x,m), rcin(y,m), m), or with only one factor encoded: x * y % m = rcmul(rcin(x,m), y, m). RUNTIME If the value of m in rcmul(x,y,m) is being used for the first time in a REDC function, the information required for the REDC algorithms is calculated and stored for future use, possibly replacing an already stored valued, in a table covering up to 5 (i.e. MAXREDC) values of m. The runtime required for this is about two times that required for multiplying two N-word integers. Two algorithms are available for evaluating rcmul(x,y,m), the one which is usually faster for small N is used when N < config("redc2"); the other is usually faster for larger N. If config("redc2") is set at about 90 and x and y have both been reduced modulo m, the runtime required for rcmul(x,y,m) is at most about f times the runtime required for an N-word by N-word multiplication, where f increases from about 1.3 for N = 1 to near 3 for N > 90. More runtime may be required if x and y have to be reduced modulo m. EXAMPLE Using a 64-bit machine with B = 2^32: > print rcin(4 * 5, 9), rcmul(rcin(4,9), rcin(5,9), 9), rcout(8, 9); 8 8 2 LIMITS none LIBRARY void zredcmul(REDC *rp, ZVALUE z1, ZVALUE z2, ZVALUE *res) SEE ALSO rcin, rcout, rcsq, rcpow