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Correct typos
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@@ -891,7 +891,7 @@
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*
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* pmod(ir,2,n) > pmod(pmod(ir,2,n),2,n)
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*
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* Thus, for thw Blum modulus 'n', the method outlined for srandom(ir) yields
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* Thus, for the Blum modulus 'n', the method outlined for srandom(ir) yields
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* the initial quadratic residue of:
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*
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* r = 0x748b6d882ff4b074e2f1e93a8627d626506c73ca5a62546c90f23fd7ed3e7b11e
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@@ -934,7 +934,7 @@
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* be beyond the reach for a while.
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*
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* The lengths of the two Blum probable primes 'p' and 'q' used to make up
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* the 20 Blum modului 'n=p*q' differ slightly to avoid certain
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* the 20 Blum moduli 'n=p*q' differ slightly to avoid certain
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* factorization attacks that work on numbers that are a perfect square,
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* or where the two primes are nearly the same. I elected to have the
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* sizes differ by up to 6% of the product size to avoid such attacks.
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@@ -983,7 +983,7 @@
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* where 'ip', 'iq' and 'ir' are large integers that are unlikely to be
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* 'guessed' and where numbers around the size of iq*ir are beyond
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* the current reach of the best factoring methods on the fastest
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* SGI/Cray supercomuters.
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* SGI/Cray supercomputers.
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*
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* Of course you can increase the '25' value if 1 of 4^25 odds of a
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* non-prime are too probable for you.
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@@ -2807,7 +2807,7 @@ zrandom(long cnt, ZVALUE *res)
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/*
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* If we need only part of the buffer, use
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* the top bits and keep the bottom in place.
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* If we need extactly all of the buffer,
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* If we need exactly all of the buffer,
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* process it as a partial buffer fill.
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*/
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if (dest.len <= blum.bits) {
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