convert ASCII TABs to ASCII SPACEs

Converted all ASCII tabs to ASCII spaces using a 8 character
tab stop, for all files, except for all Makefiles (plus rpm.mk).
The `git diff -w` reports no changes.
This commit is contained in:
Landon Curt Noll
2024-07-11 22:03:52 -07:00
parent fe9cefe6ef
commit db77e29a23
631 changed files with 90607 additions and 90600 deletions

View File

@@ -9,7 +9,7 @@
*
* Calc is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
* or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General
* or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General
* Public License for more details.
*
* A copy of version 2.1 of the GNU Lesser General Public License is
@@ -17,35 +17,35 @@
* received a copy with calc; if not, write to Free Software Foundation, Inc.
* 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA.
*
* Under source code control: 1990/02/15 01:50:38
* File existed as early as: before 1990
* Under source code control: 1990/02/15 01:50:38
* File existed as early as: before 1990
*
* Share and enjoy! :-) http://www.isthe.com/chongo/tech/comp/calc/
* Share and enjoy! :-) http://www.isthe.com/chongo/tech/comp/calc/
*/
/*
* Represent a fraction as sum of distinct unit fractions.
* The output is the unit fractions themselves, and in square brackets,
* the number of digits in the numerator and denominator of the value left
* to be found. Numbers larger than 3.5 become very difficult to calculate.
* to be found. Numbers larger than 3.5 become very difficult to calculate.
*/
define unitfrac(x)
{
local d, di, n;
local d, di, n;
if (x <= 0)
quit "Non-positive argument";
d = 2;
do {
n = int(1 / x) + 1;
if (n > d)
d = n;
di = 1/d;
print ' [': digits(num(x)): '/': digits(den(x)): ']',, di;
x -= di;
d++;
} while ((num(x) > 1) || (x == di) || (x == 1));
print ' [1/1]',, x;
if (x <= 0)
quit "Non-positive argument";
d = 2;
do {
n = int(1 / x) + 1;
if (n > d)
d = n;
di = 1/d;
print ' [': digits(num(x)): '/': digits(den(x)): ']',, di;
x -= di;
d++;
} while ((num(x) > 1) || (x == di) || (x == 1));
print ' [1/1]',, x;
}