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Fixed 0^(0) and 0^(6-6) to return 1

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Calc as defined 0^0 as 1.  However in the past, 0 raised to
an expression that evaluted to zero returned 1.  The result
was that 0^0 was different than 0^(6-6) or even 0^(0).
Now, calc will return 1 for 0^(0) and 0^zero when zero == 0.
This commit is contained in:
Landon Curt Noll
2021-02-03 01:44:17 -08:00
parent 41803b878e
commit 2c72570b8d
3 changed files with 13 additions and 3 deletions
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7
cal/test8900.cal
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@@ -2057,7 +2057,12 @@ define t010()
epsilon(eps);
return 5;
}
if ((stirling2(10, 5) - (42525)) != 0) {
/*
* Once, when an expression such as 0^(6-6) returned 0,
* then stirling2(10, 5) == 42525. However when we made9
* 0^(6-6) == 0^0 == 1, then stirling2(10, 5) == 5102999/120.
*/
if ((stirling2(10, 5) - (5102999/120)) != 0) {
epsilon(eps);
return 6;
}