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Clarify when factor() builtin returns 1

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Clarify that the factor() builtin return 1
if it does not find a factor below the limit.
This commit is contained in:
Landon Curt Noll
2021-02-03 12:45:10 -08:00
parent 8684e1be9c
commit 0f902b95cf
1 changed files with 3 additions and 2 deletions
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@@ -16,7 +16,8 @@ DESCRIPTION
assume n and limit are both nonnegative. assume n and limit are both nonnegative.
If n has a prime proper factor less than or equal to limit, then If n has a prime proper factor less than or equal to limit, then
factor(n, limit) returns the smallest such factor. factor(n, limit) returns the smallest such factor, or 1 if no
factor was found below the limit.
NOTE: A proper factor of n>1 is a factor < n. In other words, NOTE: A proper factor of n>1 is a factor < n. In other words,
for n>1 is not a proper factor of itself. The value 1 for n>1 is not a proper factor of itself. The value 1
@@ -50,7 +51,7 @@ SEE ALSO
isprime, lfactor, nextcand, nextprime, prevcand, prevprime, isprime, lfactor, nextcand, nextprime, prevcand, prevprime,
pfact, pix, ptest pfact, pix, ptest
## Copyright (C) 1999-2006 Landon Curt Noll ## Copyright (C) 1999-2006,2021 Landon Curt Noll
## ##
## Calc is open software; you can redistribute it and/or modify it under ## Calc is open software; you can redistribute it and/or modify it under
## the terms of the version 2.1 of the GNU Lesser General Public License ## the terms of the version 2.1 of the GNU Lesser General Public License